Math, asked by tirthpatel48125, 3 months ago

find the area of a triangle whose base is 4 cm and altitued is 6 cm​

Answers

Answered by thebrainlykapil
14

Given :-

  • Shape = Triangle
  • Base of Triangle = 4cm
  • Height of Triangle = 6cm

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To Find :-

  • Area of the Triangle

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Solution :-

➞ Area of Triangle = ½ × base x height

➞ Area of Triangle = ½ × 4 x 6

➞ Area of Triangle = 2 x 6

➞ Area of Triangle = 12cm

Therefore, Area of Triangle = 12cm

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Additional Info :

Formulas Related to Area :

  • Area of Square = Side x Side
  • Area of Rectangle = Length × Breadth
  • Area of Triangle = ½ × base x height
  • Area of parallelogram = base x height
  • Area of circle = πr²
  • Area of Rhombus = ½ × product of its diagonals
  • Area of Trapezium = ½ × height × sum of parallel sides
  • Area of Polygon = sum of the area of all regions into which it is divided

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Answered by RoseyThorn
4

Question ::-

find the area of a triangle whose base is 4 cm and altitued is 6 cm ?

Given ::-

  • Base of triangle = 4 cm

  • Altitude of triangle = 6 cm

To find ::-

  • Find the area of triangle ?

Solution ::-

• Base of triangle = 4 cm

• Altitude of triangle = 6 cm

➠ Area of triangle =  \dfrac{1}{2} × base × height

➠ Area =  \dfrac{1}{2} × 4 × 6

➠ Area =  \dfrac{1}{\cancel{2}} × {\cancel{4}} × 6

➠ Area = 2 × 6

➠ Area = 12 cm

_________

Area of triangle = 12 cm.

  • Area of triangle when sides are given ::-

⠀⠀⠀ \sqrt{s(s - a)(s - b)(s - c)}

  • Where , s =  \dfrac{a + b + c}{2}

  • A , B , C are sides of triangle.

  • Symbol of triangle is
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