Question

find the area of a triangle whose base is 4 cm and altitued is 6 cm​

Answer 1

Given :-

• Shape = Triangle
• Base of Triangle = 4cm
• Height of Triangle = 6cm

To Find :-

• Area of the Triangle

Solution :-

➞ Area of Triangle = ½ × base x height

➞ Area of Triangle = ½ × 4 x 6

➞ Area of Triangle = 2 x 6

➞ Area of Triangle = 12cm

Therefore, Area of Triangle = 12cm

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★ Additional Info :

Formulas Related to Area :

• Area of Square = Side x Side
• Area of Rectangle = Length × Breadth
• Area of Triangle = ½ × base x height
• Area of parallelogram = base x height
• Area of circle = πr²
• Area of Rhombus = ½ × product of its diagonals
• Area of Trapezium = ½ × height × sum of parallel sides
• Area of Polygon = sum of the area of all regions into which it is divided

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Answer 2

Question ::-

find the area of a triangle whose base is 4 cm and altitued is 6 cm ?

Given ::-

• Base of triangle = 4 cm

• Altitude of triangle = 6 cm

To find ::-

• Find the area of triangle ?

Solution ::-

• Base of triangle = 4 cm

• Altitude of triangle = 6 cm

$➠$ Area of triangle = $\dfrac{1}{2}$ × base × height

$➠$ Area = $\dfrac{1}{2}$ × 4 × 6

$➠$ Area = $\dfrac{1}{\cancel{2}}$ × ${\cancel{4}}$ × 6

$➠$ Area = 2 × 6

$➠$ Area = 12 cm

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Area of triangle = 12 cm.

• Area of triangle when sides are given ::-

⠀⠀⠀$\sqrt{s(s - a)(s - b)(s - c)}$

• Where , s = $\dfrac{a + b + c}{2}$

• A , B , C are sides of triangle.

• Symbol of triangle is ▲