Question

find the area of a triangle whose base is 52 cm and hypotenuse is 65 cm​

Answer 1

The length of the other perpendicular side

$=\sqrt{ {(65)}^{2} - {(52)}^{2} } \\ = \sqrt{4225 - 2705} \\ = \sqrt{1520} = 38.98$

Because it's a right angled triangle.

Area of this right angled triangle

$= \frac{1}{2} \times 38.98 \times 52 \\ = \frac{1}{2} \times 2026.96 = 1013.48$

Answer 2

First we have to use Pythagoras theorem

(Altitude)^2=(Hypotenuse)^2-(Base)^2

= (65)^2-(52)^2

=4225-2704

=1521

=39

Area of triangle=1/2×base×height

=1/2×52×39=26×39=1014cm^2