Question

find the area of a triangle whose breadth is 6cm , height is 11 cm.​

Answer 1

$\sf\blue{Area \: of \: \triangle = \frac{1} {2} \times base\times height}$

$\sf\purple{Area \: of \: \triangle = \frac{1} {\cancel2} \times \cancel6\times 11}$

$\sf{\pink{ \fcolorbox{blue}{green}{Area \: of \: triangle = 11×3 = 33}}}$

Answer 2

$\huge\star\mathcal{\pink{Required\:Answer}}$

$important \: notice \: = >$

To find a triangles area = >

• Breadth is not considered as main.
• Base can be only make the solution.

$solution = > \\ a = \frac{h _{b}b}{2} \\ h_{b} = 11 \\ b = 6 \\ a= 33$

$area\:of\:triangle\:=>\:33$

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