Question

find the area of a triangle whose dimensions are 18 cm ,10 cm,14 cm
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Answer 1

$\sf \bigstar \underline \blue{Given,}$

The dimensions of the triangle are 18cm, 10cm and 14cm.

$\sf \bigstar \underline \pink{To \: find :-}$

The Area of the given triangle

$\sf \bigstar \underline \orange{Solution:-}$

In this case, we apply to Heron's formula, to calculate the area of the traingle.

At first we have to calculate the semi Perimeter (S) of the given triangle.

Perimeter of the triangle ↷

$\frac{a + b + c}{2}$

$= \frac{18 + 10 + 14}{2} = \frac{42}{2} = 21$

Area of triangle ↷

$\sqrt{s(s - a)( s- b)(s - c)}$

$\sqrt{21(21 - 18)(21 - 10)(21 - 14)}$

$\sqrt{21 \times 3 \times 11 \times 7}$

$\sqrt{4851}$

$= 69.64cm {}^{2}$

Hence, the approximate area of the given triangle is 62.64cm2