find the area of a triangle whose height is x^4 +y^4 and base is 14xy
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Answered by
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when in question , no description of triangle types then we used simple area find formula of triangle.
area of triangle = 1/2 × base × height
= 1/2 × 14xy × (x^4 + y^4 )
= 7xy × (x^4 + y^4)
I hope that answer help you.
thanks
area of triangle = 1/2 × base × height
= 1/2 × 14xy × (x^4 + y^4 )
= 7xy × (x^4 + y^4)
I hope that answer help you.
thanks
Answered by
0
: If the height of a triangle is x⁴+y⁴ and its base is 14xy find the area of the triangle ?
:
Area of ∆ = 7x⁵y+7xy⁵
:
Given :
Height of the ∆ = x⁴ + y⁴
Base of it's ∆ = 14xy
: find the area of the triangle ?
:
Area of ∆ = 1/ 2 × Base × Height
Area of ∆ = 1/2 × 14xy × ( x⁴ + y⁴ )
Area of ∆ = 7xy × x⁴ + y⁴
:
Area of ∆ = 7x⁵y+7xy⁵
:
Given :
Height of the ∆ = x⁴ + y⁴
Base of it's ∆ = 14xy
: find the area of the triangle ?
:
Area of ∆ = 1/ 2 × Base × Height
Area of ∆ = 1/2 × 14xy × ( x⁴ + y⁴ )
Area of ∆ = 7xy × x⁴ + y⁴
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