find the area of a triangle whose length of sides are 13 cm 13 cm and 10 cm
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then it must be isosceles triangle
draw the perpendicular bisector
suppose ABC is Triangle And AD is AB=13 AC=13 BC=10 perpendicular bisector
in Triangle ADC DC= √ 13²-5²
DC= √169-25
DC= .√144
DC = 12
area of triangle = 1/2*10*12
= 10*6
= 60 cm²
draw the perpendicular bisector
suppose ABC is Triangle And AD is AB=13 AC=13 BC=10 perpendicular bisector
in Triangle ADC DC= √ 13²-5²
DC= √169-25
DC= .√144
DC = 12
area of triangle = 1/2*10*12
= 10*6
= 60 cm²
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