Question

find the area of a triangle whose perimeter is 180 cm.and two of its sides are 80 cm and 18 cm. Hence calculate the altitude of the triangle taking the longest side as base.​

Answer 1

Answer:

area = 720 cm, altitude = 17.56 cm

Step-by-step explanation:

side 1 = 80 cm, side 2 = 18 cm and side 3 = 180 - (80+18) = 82 cm

area = √s(s-a)(s-b)(s-c)

s = perimeter/2

s = 180/2

s = 90

area = √90(90-80)(90-18)(90-82)

area = √90*10*72*8

area = √518400

area = 720 cm

a = b*h/2

720 = 82*h/2

720*2 = 82*h

1440 = 82*h

h = 1440/82

h = 17.56 cm

Hope it helps you.

Answer 2

side 1 = 80 cm, side 2 = 18 cm and side 3 = 180 - (80+18) = 82 cm

area = √s(s-a)(s-b)(s-c)

s = perimeter/2

s = 180/2

s = 90

area = √90(90-80)(90-18)(90-82)

area = √90*10*72*8

area = √518400

area = 720 cm

a = b*h/2

720 = 82*h/2

720*2 = 82*h

1440 = 82*h

h = 1440/82

h = 17.56 cm

pls mark brainiest