Math, asked by mehmood9312798196, 2 months ago

Find the area of a triangle whose perimeter is 180 cm and two of its sides are 80 cm and 18 cm. Hence calculate the altitude of the triangle taking the longest side as base.

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Answered by ghanshyamkoche786
2

Answer:

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1)

perimeter =180cm

18+80+third side =180

98+ x =180

x=180-98

x=82 cm

2)take all sides like

a=18,b=80,c=82

s= perimeter/2 = 180/2=90

s-a =90-18=72

s-b=90-80=10

s-c=90-82=8

area = root s(s-a)(s-b)(s-c)

= root 90*72*10*8

=root 90*90*8*8

=720 square cm

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