Question

Find the area of a triangle whose perimeter is 180 CM and it's two sides are 80 cm and 18 cm.

Calculate the altitude of triangle corresponding to it's shortest side.​

Answer 1

Answer:

length of the two sides are: 80 cm and 18 cm

perimeter of the triangle= 180 cm

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$\therefore \: third \: side = 180 - (80 + 18) = 180 - 98 = 82 \: cm$

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here,

1st side, a = 80 cm

2nd side, b= 18 cm

3rd side, c = 82 cm

semi perimeter, s = 180/2 = 90

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we know,

area of a triangle

$= \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{90(90 - 80)(90 - 18)(90 - 82)} \\ = \sqrt{90 \times 10 \times 72 \times 8} \\ = \sqrt{518400} \\ = 720$

Answer 2

Step-by-step explanation:

perimeter of triangle=sum of all sides

180cm= 80+18+x

180 =98+x

180-98= x

82 =x