Find the area of a triangle whose perimeter is 180 cm and it’s two sides are 80 cm and 18 cm. Also calculate the altitude are responding to the shortest side.
Answers
Answered by
2
Third side=180-(80+18)=180-98=82
2s=180
s=90
area of triangle=√s(s-a)(s-b)(s-c)
√90(90-80)(90-18)(90-82)
√90×10×72×8
√900×72×8
√64800×8
√518400
720cm
Therefore,area of triangle= 1/2×base×height
720=1/2×18×height
So,height=80
2s=180
s=90
area of triangle=√s(s-a)(s-b)(s-c)
√90(90-80)(90-18)(90-82)
√90×10×72×8
√900×72×8
√64800×8
√518400
720cm
Therefore,area of triangle= 1/2×base×height
720=1/2×18×height
So,height=80
Similar questions