Find the area of a triangle whose perimeter is 180cm and 2 of its sides are 80cm and 18cm.also calculate the altitude of the triangle corrosponding to the shortest side.
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area of a triangle is = 720 M^2
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1)
perimeter =180cm
18+80+third side =180
98+ x =180
x=180-98
x=82 cm
2)take all sides like
a=18,b=80,c=82
s= perimeter/2 = 180/2=90
s-a =90-18=72
s-b=90-80=10
s-c=90-82=8
area = root s(s-a)(s-b)(s-c)
= root 90*72*10*8
=root 90*90*8*8
=720 square cm
3) shortest side =base =18 cm
area =720
1/2*base* altitude(h)= 720
h= 720*2/18
h=80cm
perimeter =180cm
18+80+third side =180
98+ x =180
x=180-98
x=82 cm
2)take all sides like
a=18,b=80,c=82
s= perimeter/2 = 180/2=90
s-a =90-18=72
s-b=90-80=10
s-c=90-82=8
area = root s(s-a)(s-b)(s-c)
= root 90*72*10*8
=root 90*90*8*8
=720 square cm
3) shortest side =base =18 cm
area =720
1/2*base* altitude(h)= 720
h= 720*2/18
h=80cm
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