Question

find the area of a triangle whose perimeter is 22cm, one side is 9cm and the difference of other two sides is 3cm

Answer 1

let the other two sides are x and ,

if their difference is 3 

then x-y=3

perimeter = sum of all sides

here, perimeter = 9+(x-y)+2y

22=9+3+2y

22-9-3=2y

22-12=2y

10=2y

10/2=y

y=5cm 

then other side will be x-5=3

x =3+5

x=8cm 

then, sides are 9,8,5

area by heron formula,

semi perimeter = 22/2 = 11cm

area = root [11*(11-9)(11-8)(11-5)}

area = root [11*2*3*6]

area = root [396]

area = 19.899 

i hope this will help you