find the area of a triangle whose perimeter is 42 and two of the equal sides are 8
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Answered by
1
Answer:
Perimeter = sum of all sides
42= 8+8+s
42-19=s
s=23
Area = 1/2×h×b
Area=1/2×8×23
Area=4×23
Area=92
Answered by
0
Answer:
answer is 32 8 multiple times 4 so thar
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