Question

find the area of a triangle whose perimeter is 42 cm, longest side is 15 cm and the difference of the other two sides is 1 cm.​

Answer 1

Answer:

84cm^2

Step-by-step explanation:

perimeter= 42.

longest side be x=15cm

difference of the other 2 side is 1

(y-z=1)

y=1+z

perimeter=x+y+z

42=15+1+z+z

42=16+2z

42-16=2z

26=2z

26/2=z

z=13

y=1+z

=1+13

=14

Area:-

s=(a+b+c)/2

s=42/2

s=21

Area⬇️

$\sqrt{s(s - x)(s -y )(s - z)}$

$\sqrt{21(21 - 13)(21 - 14)(21 - 15)} \\ \sqrt{21(8)(7)(6)} \\ \sqrt{7 \times 3 \times 2 \times 2 \times 2 \times 7 \times 3 \times 2} \\ 7 \times 3 \times 2 \times 2 \\ 84cm^{2}$

Answer 2

Step-by-step explanation:

hope this helps u

have a nice day