Question

find the area of a triangle whose perimeter iss 180m and two of its sides are 82cm
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

 area of a triangle = 652.87 Sq cm

Step-by-step explanation:

Consider a triangle,

Let us consider sides of traingle as a, b, c

a= 82 cm

b= 82 cm

perimter of traingle = 180 m

a + b +c = 180

c= 180 - 82 -82

c= 16 cm

Heron’s formula we get area of triangle  = $\sqrt{s (s-a) (s-b) (s-c)}$

s=( a+b+c)/2

s= (82 + 82+ 16)/2

s= 180/2

s=90

Substitute values,

Area of traingle = $\sqrt{90 (90-82) (90-82) (90-16)}$

                          =$\sqrt{90 * 8 * 8* 74}$

                          =$\sqrt{426240}$

                          = 652.87 Sq cm