find the area of a triangle whose ratices are (1,-1)(-4,6)&(-3,-5
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these are vertices,
when vertices of a triangle given then formula is
A= 1/2 ×[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]
on substitution of values,
Area= 1/2 ×[1(6-5) +(-4)(5+1) +(-3)(-1-6)]
=1/2×(11+16+21)
=24
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