Question

Find the area of a triangle whose side is 50 cm 48 cm and 14 cm
Find the area whose side is 50 cm 48 CM 14 cm

Answer 1

$semi \: perimeter \: of \: triangle \\ = \frac{a + b + c}{2} = \frac{50 + 48 + 14}{2} \\ = \frac{112}{2} = 56 \: cm$
Now,
$Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{56(56 - 50)(56 - 48)(56 - 14)} \\ = \sqrt{56 \times 6 \times 8 \times 42} \\ = \sqrt{56 \times 48 \times 42} \\ = \sqrt{112896} = 336 \: {cm}^{2}$