Question

Find the area of ​​a triangle whose side length is 50 cm with the help of Heron's formula.​

Answer 1

Answer:

Answer :-

{\underline{\boxed{\sf Area = 200\sqrt{6}}}

Step-by-step explanation :-

Heron's Formula :-

\sqrt{s(s-a)(s-b)(s-c)}

s(s−a)(s−b)(s−c)

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S = a + b + c /2

= 50 + 50 + 20/2

= 120/2

= 60

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Substituting values in formula :-

= \sqrt{s(s-a)(s-b)(s-c)}

s(s−a)(s−b)(s−c)

= \sqrt{60(60-50)(60-50)(60-20)

= \sqrt{60*10*10*40}

60∗10∗10∗40

= \sqrt{2*2*3*5*2*5*2*5*2*2*2*5}

2∗2∗3∗5∗2∗5∗2∗5∗2∗2∗2∗5

= 200\sqrt{6}200

6

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Therefore the area of triangle is 200√6