Question

find the area of a triangle whose side of which are 18 cm 10 cm the perimeter is 42 CM

no faltu answer ❌❌​

Answer 1

Answer:

hope this will help you

Explanation:

let ABC is a triangle

AB= 18 cm

BC= 10 cm

AC= x

perimeter of ∆ABC = 42 cm

AB+BC+AC= 42

18+10+AC=42

AC=42-28

AC= 14 CM

Now,

sum of sides (s) = 18+10+14/3= 14

• s less than 18

Therefore area of triangle can't find.

Answer 2

in making explain ur answer

$\huge \sf { \fcolorbox{green}{g}{Answer࿐}}$

\huge \sf

$\Large{\underline{\underline{\sf{Given:}}}}$

• Sides of triangle are 18cm and 10cm

• Perimeter of triangle is 42cm

\Larg

$\Large{\underline{\underline{\sf{Find:}}}}$

• Area of triangle

and we also need

• Third side of triangle

\Large{

$</p><p>\Large{\underline{\underline{\sf{Solution:}}}}$

Area of triangle = base × height / 2

= 18 cm × 10 cm / 2

= 180 cm / 2

= 90 cm

Perimeter of triangle = height + base + side

42 cm = 18cm + 10cm+ 3rd side

42 cm = 28 cm + 3rd side

42 cm - 28 cm = 3rd side

14 cm = 3rd side