find the area of a triangle whose sides are 1.a=3m,b=4m,c=5m
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hey here is your answer......
a=3m
b=4m
c=5m
16
here c^2=25..
a^2=9
b^2=16
here we can see that a^2+b^2=c^2
so it is right angle triangle.
in right angle triangle base=3m
perpendicular=4m
so area of right angle triangle =1/2×base × perpendicular
=1/2×3×4
=6m^2
hope it's helpful to you.....
a=3m
b=4m
c=5m
16
here c^2=25..
a^2=9
b^2=16
here we can see that a^2+b^2=c^2
so it is right angle triangle.
in right angle triangle base=3m
perpendicular=4m
so area of right angle triangle =1/2×base × perpendicular
=1/2×3×4
=6m^2
hope it's helpful to you.....
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0
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