Question

find the area of a triangle whose sides are 10cm, 12cm,14cm​

Answer 1

Answer:

Area of triangle =24√6cm square

Step-by-step explanation:

s=a+b+c/2=10+12+14 /2 =36/2=18cm

s=18cm

Area of triangle =√s(s-a)(s-b)(s-c)

=√18(18-10)(18-12)(18-14)

=√18(8)(6)(4)

=√18×8×6×4

=√3×3×2×2×2×2×2×3×2×2

=3×2×2×2√2×3

=24√6cm square

Answer 2

Step-by-step explanation:

The area of a triangle when the lengths of the three sides a, b, c are known is given by the Heron’s formula viz.,

Sq rt {s(s-a)(s-b)(s-c)} where s is the semi-perimeter of the triangle ………(1)

Now s = (a+b+c)/2 = (12+14+10)/2 = 18, s-a = 18–12 = 6, s-b = 18–14 =4 and s-c= 18–10 =8

Substituting theses values in (1) we have, sq rt {18(6)(4)(8) = 24 (rt 6) = 58.79 (approx)

Therefore, the area of the required triangle is 58.79 sq.cm (approx.)

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