Question

find the area of a triangle whose sides are 11 metre 60 M and 61 m

Answer 1

Hey friend,
Here is the answer you were looking for:

Given,
The sides of triangle are 11m , 60m and 61m

$semi - perimeter = \frac{a + b + c}{2} \\ \\ let \: a \: be \: 11m \\ b \: be \: 60m \\ and \: c \: be \: 61m \\ \\ s = \frac{11 + 60 + 61}{2} \\ \\ s = \frac{132}{2} \\ \\ s = 66 \\ \\ area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{66(66 - 11)(66 - 60)(66 - 61)} \\ \\ = \sqrt{66(55)(6)(5)} \\ \\ = \sqrt{66 \times 55 \times 6 \times 5} \\ \\ = \sqrt{108900} \\ \\ = 330$

Area of triangle = 330 cm^2

Hope this helps!!!!

@Mahak24

Thanks...
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