Find the area of a triangle whose sides are 11m, 60m and 61m
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By using Herons formula u can find the area of the triangle
Area of the triangle=√s(s-a)(s-b)(s-c)
Let a=11m
b=60m
c=61m
s=(a+b+c)÷2
=(11+60+61)÷2 ∴s=66m
=132÷2 = 66m
As I said Area =√s(s-a)(s-b)(s-c)
=√66(66-11)(66-60)(66-61)
=√66×55×6×5
We can take the common factors outside
=√6×11×5×11×6×5
By removing the roots we will get
=6×11×5
=330m²
Pls check before doing
You can also find 's' if you are given the perimeter
s=perimeter÷2
Area of the triangle=√s(s-a)(s-b)(s-c)
Let a=11m
b=60m
c=61m
s=(a+b+c)÷2
=(11+60+61)÷2 ∴s=66m
=132÷2 = 66m
As I said Area =√s(s-a)(s-b)(s-c)
=√66(66-11)(66-60)(66-61)
=√66×55×6×5
We can take the common factors outside
=√6×11×5×11×6×5
By removing the roots we will get
=6×11×5
=330m²
Pls check before doing
You can also find 's' if you are given the perimeter
s=perimeter÷2
meekshimeenu:
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