Question

find the area of a triangle whose sides are 12 centimetre 16 cm and 20 CM respectively

Answer 1

Answer:

Answer is

$96 \: c{m}^{2}$

Explanation:

Use this formula-

$\sqrt{s(s - a)(s - b)(s - c)}$

Here,

S-semi perimeter

a,b,c -sides of triangle

$s = \frac{a + b + c}{2}$

a=12

b=16

c=20

$s = \frac{12 + 16 + 20}{2} \\ \\ s = \frac{48}{2} = 24$

put values of s and a,b,c in formula

$area = \sqrt{(24)(24 - 12)(24 - 16)(24 - 20)} \\ = \sqrt{24 \times (12) \times (8) \times (4)} \\ \\ = 12 \sqrt{2 \times 8 \times 4} \\ = 12 \times 8 \\ 96 \: c{m}^{2}$