Question

find the area of a triangle whose sides are 12cm 18cm and 20cm respectively
.

Answer 1

$\sqrt{s (s-a) (s-b) (s-c)}$

$s = \frac{a+b+c}{2}$

$s = \frac{12+18+20(cm)}{2}$

$s = \frac{50(cm)}{2}$

$s = 25cm$

$\sqrt{25 (25-12) (25-18) (25-20)}$

$\sqrt{25 (13) (7) (5)}$

$\sqrt{5×5×13×7×5}$

$5 \sqrt{13×7×5}$

$5 \sqrt {455}$


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