find the area of a triangle whose sides are 13 cm 20 cm and 21 CM also find attitudinal of the triangle corresponding
to the largest side
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Answer:
s = (13+20+21)/2 = 54/2 = 27
area = √(27)(27-13)(27-20)(27-21)
= √(3³)(7)(2)(7)(2)(3)
= √(3⁴)(7²)(2²)
= 3².7.2 = 14×9 = 126
area = 126cm²
area = 1/2 (base)(height)
=> 126 = 1/2 (21)(height)
=> altitude length = 12cm
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