Math, asked by riyasrivastava358, 5 months ago

find the area of a triangle whose sides are 13 cm 20 cm and 21 CM also find attitudinal of the triangle corresponding
to the largest side​

Answers

Answered by dsk75
0

Answer:

s = (13+20+21)/2 = 54/2 = 27

area = √(27)(27-13)(27-20)(27-21)

= √(3³)(7)(2)(7)(2)(3)

= √(3⁴)(7²)(2²)

= 3².7.2 = 14×9 = 126

area = 126cm²

area = 1/2 (base)(height)

=> 126 = 1/2 (21)(height)

=> altitude length = 12cm

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