Question

find the area of a triangle whose sides are 17cm10cm and9cm,​

Answer 1

Answer:

area is 1/2 of base * height so are will depend upon what u may take as a base and height

Step-by-step explanation:

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=36\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =17 cm,10 cm,9 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{17+10+9}{2} \\ \\ : \implies s = \frac{36}{2} \\ \\ \green{ : \implies s =18 } \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{18(18- 17)(18-10)(18- 9)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{18\times 1\times8\times 9} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{1296} \\ \\ : \implies \text{Area \: of \: triangle =}36\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle =36\: {cm}}^{2} }$