Math, asked by geethikakakarlapudi, 4 months ago

find the area of a triangle whose sides are 18 cm,10 cm, and 14cm

Answers

Answered by induu2345

1

Step-by-step explanation:

s = 18+10+14/2

s = 42/2

s =21

area of traingle = sq.root 21(21-18)(21-10)(21-14)

= sq.root 21(3)(11)(7)

= sq.root (3)(7)(3)(11)(7)

= 21sq.root (11)

Answered by swatianurish

0

Answer:

69.577295147196

Step-by-step explanation:

area of a scalene triangle = $\sqrt{s(s-a)(s-b)(s-c)}$ = $\sqrt{21*3*11*7}$ =69.577295147196

s= semi perimeter = $\frac{18+10+14}{2}$ = $21$

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