Math, asked by beastboy5036, 5 months ago

Find the area of a triangle whose sides are 18 cm, 24 cm and 30 cm.
Also, find the length of altitude corresponding to the largest side of the
triangle.

Answers

Answered by soumyadiproy894
7

Step-by-step explanation:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

A= s(s−a)(s−b)(s−c)

where

s= a+b+c

2

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

s= 18+24+30 =36

2

A= √36(36−18)(36−24)(36−30)

A= √36×18×12×6

A= √216×216 =216 cm^2

Largest side= 30 cm

Area of the triangle = 1 ×base×altitude=216

2

1×30× altitude=216 cm^2

2

Altitude= 216/15= 14.4cm(Ans)

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Answered by 8472
1

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