Question

Find the area of a triangle whose sides are 18cm,24cm and 30cm.Also,find the length of altitude corresponding to the largest side of the triangle.​

Answer 1

Answer:

let the sides be a,b and c.

semiperimeter (s) = (a+b+c)/2

= (28+24+30)/2

= 82/2

= 41

area of ∆ = √s(s-a)(s-b)(s-c)

= √41(41-18)(41-24)(41-30)

= √41(23)(17)(11)

= √176341

= 13.27cm²

area of ∆ = 1/2 × base × altitude (height= altitude)

Or, 13.27 = 1/2 × 30 × altitude (base=largest side)

Or, altitude = 13.27÷15

= 0.884cm.

ans

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