Math, asked by anandaniparivesh, 1 month ago

Find the area of a triangle whose sides are 20 cm, 21 cm and 29 cm by Heron’s formula,

also find the height corresponding to the longest side..​

Answers

Answered by SARGEFF
0

Answer:

a=20cm, b=21 cm and c= 29 cm

then, s=a+b+c/2

s = 20+21+29/2= 35cm

area of triangle=√s(s-a) (s-b) s-c)

=√35(35-20) (35-21) (35-29)

√35×15×14×6

=210 cm²

area of triangle=1/2 × base × height

210cm²=1/2×20×h

210÷10=h

21=h

Answered by anusrikar33
0

Answer:

210

Step-by-step explanation:

S = 20+21+29/2

= 35

A =√35(35-20)(35-21)(35-29)

=√35x15x14x6

=√44100

=210

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