Question

find the area of a triangle whose sides are 24,16,18

Answer 1

Put the unit In the answer

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle}\approx144\:cm^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =24 cm,16 cm,18 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{24+16+ 18}{2} \\ \\ : \implies s = \frac{58}{2} \\ \\ \green{ : \implies s =29 } \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{29(29- 24)(29-16)(29- 18)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{29\times 5\times 13\times 11} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{20735} \\ \\ : \implies \text{Area \: of \: triangle}\approx144\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle}\approx 144\: {cm}^{2} }$