Question

Find the area of a triangle whose sides are 24 cm, 32 cm and 40 cm. Answer the question with steps DO NOT SPAM !!

Answer 1

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Answer 2

Answer:

it's a right angled triangle

here

${h }^{2} = {p}^{2} + {b}^{2}$

${40}^{2} = {24}^{2} + {32}^{2}$

Area = 1/2×p×b

=1/2×24×32

=12×32

=384 Sq. cm.