Question

find the area of a triangle whose sides are 26 CM 28 cm and 30 cm

Answer 1

At first find semi perimeter of the triangle. Then to find area the formula is
$\sqrt{ s(s - a)(s - b)(s - c)}$
Where a, b, c are the sides of triangle. Then find the area. Tha answer comes
336 sq
cm

Answer 2

Answer:

$\text{The of triangle is }336 cm^2$

Step-by-step explanation:

Given the sides of triangle 26 cm, 28 cm and 30 cm.

we have to find the area of triangle

By heron's formula

$Area=\sqrt{s(s-a)(s-b)(s-c)}$

where s is semiperimeter i.e

$s=\frac{a+b+c}{2}$

Sides of triangle 26 cm, 28 cm and 30 cm.

$s=\frac{26+28+30}{2}=\frac{84}{2}=42 cm$

$Area=\sqrt{42(42-26)(42-28)(42-30)}$

    $=\sqrt{42\times 16\times 14\times 12}=\sqrt{112896}=336 cm^2$

$\text{The of triangle is }336 cm^2$