Question

find the area of a triangle whose sides are 29,20 and 21​

Answer 1

Answer:

the area of a triangle whose sides are 29,20 and 21​  is 210 cm square

Step-by-step explanation:

Answer 2

The area of the triangle whose sides are 29,20 and 21​ is 210 square unit

Step-by-step explanation:

Given:

The sides of a triangle as 29, 20, 21

To find out:

The area of the triangle

Solution:

We know that if sides of the triangles are a, b, c and s is the semiperimeter of the triangle where $s=(a+b+c)/2$, then the area of the triangle is given by

$A=\sqrt{s(s-a)(s-b)(s-c)}$            (Heron's formula)

Here,

$s=\frac{29+20+21}{2}=\frac{70}{2}=35$

Thus, the area

$A=\sqrt{35(35-29)(35-20)(35-21)}$

$\implies A=\sqrt{35\times 6\times 15\times 14}$

$\implies A=\sqrt{7\times 5\times 2\times 3\times 3\times 5\times 2\times 7}$

$\implies A=\sqrt{7^2\times 5^2\times 2^2\times 3^2}$

$\implies A=7\times 5\times 2\times 3$

$\implies A=210$ square units

Hope this answer is helpful.

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