Question

Find the area of a triangle whose sides are 29cm, 20 cm and 21cm

Answer 1

Semi Perimeter of the Triangle

= (29+20 +21)/2

= 35 cm

By Heron's Formula:

$\sqrt{s (s - a) (s - b) (s - c) }$

$= \sqrt{35(35 - 21)(35 - 29)(35 - 20)}$

$= \sqrt{35 \times 14 \times 6 \times 15}$

$= \sqrt{7 \times 5 \times 7 \times 2 \times 2 \times 3 \times 5 \times 3}$

$= 7 \times 5 \times 2 \times 3$

$= 210$ (ANS)

Answer 2

Given :  triangle whose sides are 20 cm, 21cm, 29 cm  

To Find :  Area of Triangle

Solution:

Sides are

20 cm

21 cm

29 cm

20² + 21²

= 400 + 441

= 841

= 29²

Hence given triangle is right angle triangle

Area of triangle = (1/2) * 20 * 21   = 210  cm²

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