Question

find the area of a triangle whose sides are 29cm,20cm,21cm​

Answer 1

Answer:

Given :  triangle whose sides are 20 cm, 21cm, 29 cm  

To Find :  the length of the altitude corresponding to the largest side

Solution:

Sides are

20 cm

21 cm

29 cm

20² + 21²

= 400 + 441

= 841

= 29²

Hence given triangle is right angle triangle

Area of triangle = (1/2) * 20 * 21   = 210  cm²

Area of triangle = (1/2) * 29 *  altitude corresponding to the largest side.

=> 210 = (1/2) * 29 *  altitude corresponding to the largest side.

=>  altitude corresponding to the largest side. = 420/29 cm

= 14.483 cm

Answer 2

Hey Mate,

Given,

a = 20 cm

b = 21 cm

c = 29 cm

Perimeter = a + b + c = 20 + 21 + 29 = 70 cm

Since, all three sides are given, we will use Heron's formula to find the area of the triangle.

Heron's Formula :-

(s)∗(s−a)∗(s−b)∗(s−c)\sqrt{(s)*(s-a)*(s-b)*(s-c)}

(s)∗(s−a)∗(s−b)∗(s−c)

( Where, s = semiperimeter or perimeter / 2 and a, b and c are the sides of the triangle )

Area of the Triangle = (35)∗(35−20)∗(35−21)∗(35−29)\sqrt{(35)*(35-20)*(35-21)*(35-29)}

(35)∗(35−20)∗(35−21)∗(35−29)

Area of the Triangle = 35∗15∗14∗6\sqrt{35*15*14*6}

35∗15∗14∗6

Area of the Triangle = 44100\sqrt{44100}

44100

Area of the Triangle = 210 sq. cm

Therefore, the area of a triangle whose sides are 20 cm, 21 cm and 29 cm is 210 sq. cm.

HOPE IT HELPS YOU!!!

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