Question

Find the area of a triangle whose sides are 34 CM 20 cm and 42 CM then find the length of altitude corresponding to shortest side

Answer 1

firstly we have to find the semi perimeter of the triangle by using formula s = a+b+c/2
s= 34cm+20cm+42cm/2
= 96cm/2
= 48cm
then , according to Heron formula
area of triangle= √(s(s-a)(s-b)(s-c)
= √48(48-34)(48-20)(48-42)
=√48×14×28×6
=336cm^2
now by using formula
Area = b×h/2
336cm^2=20cm×h/2
336cm^2= 10cm×h
h= 336cm^2/10cm
h= 33.6cm

Answer 2

hey friend
here is your answer
GIVEN : sides of triangle are 34 20 42 cm
TO FIND: area of triangle
SOLUTION: by hero's formula
S= 34+20+42/2
=96/2
=48
Area of triangle=√S(S-A) (S-B) (S-C)
=√48×14×28×6
=√16×3×7×2×7×4×3×2
=4×3×7×2×2
=336
area of triangle is 336 sq. cm.
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