find the area of a triangle whose sides are 34 CM 45 CM 50 cm
Answers
Step-by-step explanation:
use herons formula
but b4 that we need semiperimeter ie s ka value
so
s=a+b+c upon 2 where a b and c are nothing but sides substitute the values of respective sides so s=64.5
now apply herons formula ie
s
under root of s ×(s-a)(s-b)(s-c)
thus solving you would be getting
area as approximately 745.81
remember it is root so dont forget to take square root of the answer u had find after multiplying that s×(s-a)(s-b)(s-c)
ohk
Answer :
- Area of triangle is 745.814 cm²
Given :
- Area of triangle whose sides are 34cm ,45cm and 50cm
To find :
- Area of triangle
Solution :
As we know that
- s = (a + b + c)/2
where,
- a = 34cm
- b = 45cm
- c = 50cm
》s = (a + b + c)/2
》(34 + 45 + 50)/2
》129/2
》64.5 cm
》s = 64.5cm
Then,
According to heron's formula we know that ,
- Area of triangle = √s(s - a) (s - b) (s - c)
Where, s is semi- Perimeter and A is area
》A = √[s(s - a) (s - b) (s - c)]
》A = √[64.5(64.5- 34) (64.5 - 45) (64.5 - 50)]
》A = √[64.5(30.5) (19.5) (14.5)]
》A = √[64.5 × 30.5 × 19.5 × 14.5]
》A = √556239
》 A = 745.814 cm²
Hence , Area of triangle is 745.814 cm²