Find the area of a triangle whose sides are 3cm ,4cm and 5cm respectively
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Answered by
23
Let a=3cm b=4cm c=5cm
Therefore by heron's formula
s=a+b+c /2
=3cm +4cm+5cm/2
= 12/2
=6cm
therefore area of triangle=√s(s-a) (s-b) (s-c)
=√6cm(6cm-3cm)(6cm-4cm)(6cm-5cm)
=√6cm×3cm×2cm×1cm
=√36
=6cm sq.
Therefore by heron's formula
s=a+b+c /2
=3cm +4cm+5cm/2
= 12/2
=6cm
therefore area of triangle=√s(s-a) (s-b) (s-c)
=√6cm(6cm-3cm)(6cm-4cm)(6cm-5cm)
=√6cm×3cm×2cm×1cm
=√36
=6cm sq.
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19
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See the attached file
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