Question

find the area of a triangle whose sides are 40 cm 24 cm and 32 cm

Answer 1

Answer:

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Answer 2

The area of the triangle is 384 sq. cm.

Explanation:

Heron's Formula,

Area of triangle with sides a, b , c is given by :-

$A=\sqrt{s(s-a)(s-b)(s-c)}$ , where s is semi-perimeter.

Given : Sides of triangle =40 cm  ,24 cm and 32 cm .

$s=\dfrac{40+24+32}{2}=\dfrac{96}{2}=48$

Then, area of triangle = $\sqrt{48(48-40)(48-24)(48-32)}$

$=\sqrt{48\times8\times24\times16}\\\\=\sqrt{147456}=384\ cm^2$

Hence, the area of the triangle is 384 sq. cm.

# Learn more :

Calculate the area of triangle whose sides are 18 cm 24 cm and 30 cm

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