Find the area of a triangle whose sides are 41 cm, 15cm, and 28 cm.
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Answer:
126 CM^ Is the answer of triangle
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Area= √s(s-a) (s-b) ( s-c)
where s is
s= perimeter/2 = 41+15+28/2 = 84/2 = 42
area = √ 42 (42-41)(42-15)+(42-28)
= √ 42 ×1×27×14
= √15876cm²
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