Question

find the area of a triangle whose sides are 72cm,48cm,36cm
give step by step answer
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Answer 1

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Sides of triangle = 72cm , 48cm , 36cm

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Area = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

$\sf{\red{\boxed{\bold{area = \sqrt{s(s-a)(s-b)(s-c)}}}}}$

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$\sf{\red{\boxed{\bold{Semi\:Perimeter = \dfrac{ a + b + c }{2}}}}}$

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$\sf: \implies\: {\bold{ Semi\: Perimeter = \dfrac{ 72 + 48 + 36}{2}}}$

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$\sf: \implies\: {\bold{ Semi\: Perimeter = \dfrac{ 156}{2}}}$

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$\sf: \implies\: {\bold{ Semi\: Perimeter = 78}}$

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$\sf: \implies\: {\bold{ Area= \sqrt{78( 78 - 72)( 78 - 48)( 78 + 36)}}}$

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$\sf: \implies\: {\bold{ Area= \sqrt{78\times 6\times 30\times 36 }}}$

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$\sf: \implies\: {\bold{ Area= \sqrt{2\times 36 \times 2\times 3\times 3\times 10\times 36}}}$

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$\sf: \implies\: {\bold{ Area= 2 \times 36\times 3 \sqrt{10}}}$

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⠀

$\sf: \implies\: {\bold{ Area= 36\times 6\sqrt{10}}}$

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$\sf: \implies\: {\bold{ Area= 216\sqrt{10}cm^2}}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Area of triangle is 216√10 cm^2