Question

Find the area of a triangle whose sides are 7cm 8cm 9cm

Answer 1

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=26.83\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle =7 cm,8 cm,9 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{7+8+9}{2} \\ \\ : \implies s = \frac{24}{2} \\ \\ \green{ : \implies s =12 } \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{12(12- 7)(12-8)(12- 9)} \\ \\ : \implies \text{Area \: of \: triangle =}\sqrt{12\times 5\times4\times 3} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{720} \\ \\ : \implies \text{Area \: of \: triangle =}26.83\: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle =26.83\: {cm}}^{2} }$