Question

find the area of a triangle whose sides are 8 cm 10 cm and 16 cm respectively​

Answer 1

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➡Given here .

↪Let, first Side of triangle A=8cm.

↪second side of triangle B=10cm.

↪Thired side of triangle C=16cm.

➡Let, half Perimeter P =( A+B+C)/2.

↪So P= (8+10+16)/2.

= 34/2.

= 17.

➡Area = √[p(p-A)+(p-B)+(p-C)].

= √[17(17-8)+(17-10)+(17-16)].

= √[ 17(9+7+1)].

= √[ 17×17].

= 17cm².

➡Hopes its helps u.

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Answer 2

Answer:

mad girl 34