Question

Find the area of a triangle whose sides are 9 cm, 5 cm and 5 cm

Answer 1

Answer:

But I have tell it

Step-by-step explanation:

A≈9.81cm²

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Answer 2

Answer:

9.765 [Approx.]

1st:- Triangle is isosceles

2nd:- The height divides the triangle into two congruent triangle that have a 90degree angle.

So using the Pythagorean triplet, we can find the height, but in the other way

H²(hypotenuse) = P²(perpendicular)+ B²(Base)

Hypotenuse = 5cm (because it is opposite to the perpendicular vertex of the triangle)

Base = 4.5 (because the height divides the triangle into two congruent triangles)

Perpendicular= Unknown

let the value of perpendicular be 'y'

So, this is the answer, see it carefully

5² = y² + 4.5²

25 = y² + 20.25

25 - 20.25 = y²

4.75 = y²

2.17 = y

Base = 9cm

Height = 2.17

Area = (1/2 x base x height)cm²

= (1/2 x 9 x 2.17)cm²

= (1/2 x 19.53)cm²

= 9.765cm² [approx.]

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