find the area of a triangle whose sides are 91cm,96cm,and 105cm in length.Find the height corresponding to the greatest side
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a=91
b=96
c=105
s=(91+96+105)/2=292/2=146
By using Heron's formula,
√(146-91)(146-96)(146-105)
=√55x50x41
=√11x5x2x5x5x41
=5√110x41
=5√4510 cmsq.
greatest side=105cm
5√4510=0.5x105xh
10√4510=105h
(2√4510)/21cm=h
b=96
c=105
s=(91+96+105)/2=292/2=146
By using Heron's formula,
√(146-91)(146-96)(146-105)
=√55x50x41
=√11x5x2x5x5x41
=5√110x41
=5√4510 cmsq.
greatest side=105cm
5√4510=0.5x105xh
10√4510=105h
(2√4510)/21cm=h
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