Question

find the area of a triangle whose sides are 9cm ​

Answer 1

It is an equivalent triangle
area =
$\sqrt{3} \div 4 \times {a}^{2}$
$\sqrt{3} \div 4 \times 9 \\ = 9 \sqrt{3} \div 4 {cm}^{2}$

Answer 2

If all the sides of these triangle are equal, then it's an equilateral triangle.

Area of equilateral triangle

=_/3÷4 × (side)^2

=_/3 ÷4 × (9)^2

= _/3÷4 × 81

= 81_/3÷4

= 35.07cm^2

Hope it hellpss....

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