Find the area of a triangle whose sides are a 2a and 3a/2
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Answer:
6a2
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Answered by
0
Answer:
According to question
sides of rectangle
2a , 2a , 3a , 3a
we know that,
Area of rectangle= length X breath _______equation (1)
so,
let length = 3a
breath = 2a
but the value of length and breath in equation (1)
therefore,
Area of rectangle = 3a X 2a
= 6a^{2}a
2
<== answer
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