find the area of a triangle whose sides are in ratio 5 : 12 : 13 : and its perimeter is 60 cm for class 7th
Answers
Answered by
10
LET THE SIDES OF A TRIANGLE BE 5x , 12x, 13x
perimeter = 60
5x+12x+13x=60
30x=60
x=2
SIDES ARE >>
5x=10 =a
12x=24 = b
13x=26 = c
HERON'S FORMULA ;;;;
AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)
s= perimeter /2 = 30
AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)
=√30(30-10)(30-24)(30-26)
=√3*10*2*10*2*3*2*2
=√3*3*10*10*2*2*2*2
=3*10*2*2
AEEA OF TRIANGLE = 120 cm²
perimeter = 60
5x+12x+13x=60
30x=60
x=2
SIDES ARE >>
5x=10 =a
12x=24 = b
13x=26 = c
HERON'S FORMULA ;;;;
AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)
s= perimeter /2 = 30
AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)
=√30(30-10)(30-24)(30-26)
=√3*10*2*10*2*3*2*2
=√3*3*10*10*2*2*2*2
=3*10*2*2
AEEA OF TRIANGLE = 120 cm²
khanreigns:
book ke back me answer diya hai 120cm²
BOOK KE ANSWER GALAT HO SKTE THE DEAR
ask to ur teacher
ok
aap multiply wrong ki hai 3*10=30.30*2=60.60*2=120
their for 120cm² answer........
okkk sorry
hmmmmm
Thanks
^_^
Answered by
3
let 5x ,12x,13x are sides
5x+12x+13=60
30x=60
x=2
5×2=10,12×2=24,13×2=26
s=
5x+12x+13=60
30x=60
x=2
5×2=10,12×2=24,13×2=26
s=
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