Question

find the area of a triangle whose sides are in ratio 5 : 12 : 13 : and its perimeter is 60 cm for class 7th

Answer 1

LET THE SIDES OF A TRIANGLE BE 5x , 12x, 13x

perimeter = 60
5x+12x+13x=60
30x=60
x=2

SIDES ARE >>
5x=10 =a
12x=24 = b
13x=26 = c

HERON'S FORMULA ;;;;

AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)

s= perimeter /2 = 30

AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)
=√30(30-10)(30-24)(30-26)
=√3*10*2*10*2*3*2*2
=√3*3*10*10*2*2*2*2
=3*10*2*2
AEEA OF TRIANGLE = 120 cm²

Answer 2

let 5x ,12x,13x are sides
5x+12x+13=60
30x=60
x=2
5×2=10,12×2=24,13×2=26
s=